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PLEASE HELP VERY URGENT !!.. explain ur naswer in steps...

2007-11-05 05:04:36 · 7 answers · asked by iju 2 in Science & Mathematics Mathematics

7 answers

ok, so the total right now is 8 liters
and 40% of that is acid

so, 40% of 8 liters = 3.2 liters of acid.

you've got 3.2 L of acid in the 8 liters total.

now you want it so that the 3.2 liters of acid is 10% of the total.


10% of Total = 3.2 Liters

divide by 10%
Total = 32 Liters

but you started with 8 Liters

so you need to add 32 - 8 or 24 liters of water.

2007-11-05 05:17:34 · answer #1 · answered by Ms. M 3 · 0 0

Simple:

You are reducing the concentration of acid from 40% to 10%, so the desired result is only 25% as strong as the original solution. It takes 3 times as much water as the current solution to achieve that result. 8 X 3 = 24 litres...

2007-11-05 05:15:17 · answer #2 · answered by DAVID T 2 · 0 0

40% of 8 litres of your solution is acid, so you have 3.2 litres of pure acid.
algebriacly
one can add x litres to get a 10% solution. Since you are not adding acid.
.10*(8 + x) = 3.2
8 + x = 32
x = 24

2007-11-05 05:17:36 · answer #3 · answered by Peter m 5 · 0 0

water is 0% acid and x represents # liters of water

so 0(x) + .40(8) = .10(x+8)
solve this and get x = 24 liters of water

2007-11-05 05:12:26 · answer #4 · answered by ssssh 5 · 1 0

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2016-11-10 08:45:37 · answer #5 · answered by purifory 4 · 0 0

8 * 0.4 = 3.2 liters of acid.

3.2/0.1 = 32 liters 10% solution.

Water to add = 32 - 3.2 - 8 = 20.8 liters

2007-11-05 05:09:38 · answer #6 · answered by gebobs 6 · 0 1

"sssssh" is right ;-)

2007-11-05 05:16:56 · answer #7 · answered by NewLife 2 · 0 0

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