how do you find the measure of the 3 sides on a triangle, if they already give the measure of the 3 angles??

Question

for example, the measurment of angle "R" is 40, the measurment of angle "S" is 120, and the measurement of angle "T" is 20, how do i find the side lengths to those angles

Answer 1

You can`t !
You can draw MANY triangles having these angles but having different lengths of side.

Answer 2

OK - if you only have the angles - you cannot find the sides.

You must have at least one side (and two angles) to determine the sides of a triangle.

As a previous answer has pointed out, look at equilateral triangles. All three angles are 60, but you could have infinite number of side values, all 1, all 2, all 3, etc.

So without one side, you cannot find the lengths of the sides with just the angles.

Hope that helps.

Answer 3

You can't. You need at least 1 sides length to find the other 2. There are an infinite # of triangles with those angles.

Answer 4

It's been an eon since I took geometry, but I believe you have to have more than just the three angles to determine the lengths of the sides.

Consider your basic equilateral triangle. You've got the measurements of the three angles, right? But knowing only those angles, it could be the size of your pinkie fingernail or as big as the mall parking lot, the angles unchanged.

Answer 5

It is impossible to find the lengths of the sides of a triangle based upon their angles alone. If you have one side and the three angles you can use the law of sines: (a/sin(A)) = (b/sin(B)) = (c/sin(C)). Where 'a' is the side of the triangle opposite, not touching, angle 'A'. With the information given you can create infinite similar triangles.

Answer 6

enable's label the two area as a,b, and c. So then this problem turns into: a+b+c=fifty seven b=a+2 c=b+2 Plug those in at the same time c=a+2+2= a+4 a+(a+2)+(a+4)=fifty seven 3a+6=fifty seven 3a=fifty one a=17 consequently b=19, c=21 17+19+21=fifty seven. tremendously much each observe problem available would properly be solved in an identical technique. Assign variables for all unknowns, and then try to locate relationships between those variables and general numbers, our one yet another. as a effect we had 3 unknowns, so we'd opt for a equipment of three autonomous equations to sparkling up it.

Answer 7

just use sine, cosine, or tangent. lol i took geometry just last year and ffs its not hard to find it out..

Answer 8

use tan. sin. and cos.