Solve Multiplce Choice. Assume the exercise describes a linear relationship.?

Question

The average value of a certain type of automobile was $14,040 in 1994 and depreciated to $4140 in 1999. Let y be the average value of the automobile in the year x, where x = 0 represents 1994. Write a linear equation that models the value of the automobile in terms of the year x.


a. y = -1980x - 5760
b. y = -1980x + 4140
c. y = -1 / 1980x - 4140
d. y = -1980x + 14, 040

Answer 1

d. y = -1980x + 14, 040

Answer 2

whilst x will improve by 0.5 (one million.50-one million.00), y lowers by 24 (102-seventy 8). So for each x enhance, there's a 40 8 shrink, so y = -48x. Then there's a 'base', the quantity offered whilst the warm canines could be thoroughly at no value. call it say B. y = -48x + B you recognize that once x is one million, y is 102, so 102 = -40 8 + B >>> B = a hundred and fifty b. y = -48x + a hundred and fifty additionally, once you knew pertaining to to the -48x, you are able to desire to've figured answer D is impossible, on condition that could desire to intend the quantity offered could constantly be damaging (till you're able to provide the purchasers approximately 3$ for each hotdog offered).