Just checking to see if I've made any mistakes in my hw problems...
1. A block of mass m is at rest on an inclined plane as shown in the figure. Find an expression for the static friction in terms of the mass , the acceleration of gravity, and and the angle shown.
1. The attempt at a solution:
http://www.physicsforums.com/attachm...3&d=1194247920
Newtons 1st Law
sum of forces = 0
mg cos(a) -μs * mg sin (a) = 0
μs = cos(a)/sin(a) = cot(a)
thus: static frictoin = cot(a)*cos(a)
2. A proud new BMW owner drivers her car at a speed of 25 m/s into a corner. The coefficients of friction between the road and the tires are 0.70 (static) and 0.40(kinetic). What is the minimum radius of curvature for the corner in order for the car not to skid?
2. Speed(v) of honda = 25 m/s
Coefficient of kinetic friction(μk) = 0.40
2007-11-05
03:08:02
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4 answers
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asked by
korr
2
in
Science & Mathematics
➔ Physics
Now formula for calculating the value of the minimum radius of curvature for the corner in order for the car not to skid is
r = v^2 / (coeff. of static kin. fric.)*gravity
thus, it's (25 m/s)^2 / 0.40 * 9.81 m/s^2 = 159.2 m
3. A 44.5-N weight is hung on a spring scale, and the scale is hung on a string. The string is lowered at a rate such that the entire assembly has downward acceleration of 4.90 m/s^2. What does the scale read?
3. sum of the forces = m*a
sum of Fy = T - w = ma
thus: (44.5 kg*m/s^2) * ((9.81 m/s^2 - 4.90 m/s^2) / 9.81 m/s^2) = 22.3 N
2007-11-05
03:08:24 ·
update #1