2007-11-05 00:29:13 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Well... you can...
3x² + 1 = 0
3x² = -1
x² = -⅓
x = ±√-⅓
x = ±i ⅓√3
3(x + i ⅓√3)(x - i ⅓√3)
I have factored it into two binomials... two factors... each containing an imaginary root.
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Thanks Nester... I fixed it.
2007-11-05 00:43:33 · answer #1 · answered by Anonymous · 0⤊ 1⤋
Cogito has forgotten to multiply by 3 !
Another way is :
3x² + 1 = 3x² - (-1) = (sqrt(3) x)² - i²
= (x sqrt(3) - i)(x sqrt(3) + i) with complex numbers.
2007-11-05 09:06:40 · answer #2 · answered by Nestor 5 · 1⤊ 0⤋
not possible.Both terms has no common factor.
2007-11-05 10:04:45 · answer #3 · answered by Kenneth Koh 5 · 0⤊ 0⤋
4x^2
2007-11-05 11:17:51 · answer #4 · answered by GonE 3 · 0⤊ 1⤋
you cannot
2007-11-05 08:32:17 · answer #5 · answered by someone else 7 · 0⤊ 0⤋