On the last ship raid, Seamus bagged twice as many gold coins as Davey, but they each gave 24 to Horatio , which left Seamus with five times as many coins as Davey. How many coins did Seamus have at the start?
2007-11-04 23:11:28 · 15 answers · asked by Jammy 1 in Science & Mathematics ➔ Mathematics
_________At Start_____Later
Davey____x coins_____x - 24 coins
Seamus___2x coins____2x - 24 coins
2x - 24 = 5(x - 24)
2x - 24 = 5x - 120
96 = 3x
x = 32
Seamus had 64 coins at start.
2007-11-05 04:00:49 · answer #1 · answered by Como 7 · 0⤊ 0⤋
Seamus had 32 coins to start with. Explanation
Seamus = 32
Davey = 64 (double 32)
Give 24 coins
Seamus now has = 8
Davey now has = 40
Davey has 5 times the amount
Problem Solved
2007-11-04 23:25:02 · answer #2 · answered by Ben G 1 · 1⤊ 0⤋
First, represent ur variables.
x = Davey's coins
2x =Seamus' coins
(coz Seamus bags twice as Davey)
x-24 =Davey's coins after giving some to Horatio
2x-24 =Seamus' coins after he gave some to Horatio
(coz they gave Horatio 24 coins each)
so...
2x-24=5(x-24)
(coz after Seamus lended his coins, he is now 5 times as more as Davey)
lets solve..
2x-24=5(x-24) [distribute five to the number]
2x-24=5x-120 [then transpose all numbers w/ x to the left & all pure numbers to the right. When u transpose, u change signs lyk minus become plus, times bcomes divide etc.]
-5x+2x= -120+24 [simplify]
-3x = -96
then...
x = -96/-3 [remember, dividing numbers with like signs gives positive]
so...
x =32 [remember, x is Davey's representation so we must know whats Seamus. Seamus' representation is 2x so...]
2x= 2 * 32 = 64
Seamus had 64 coins in the first place!
lets check replacing the x's with our solved numbers....
64-24=5*(32-24)
40=5*8
40=40
so tell me, am i right or wrong?
2007-11-04 23:37:42 · answer #3 · answered by Anonymous · 1⤊ 0⤋
Seamus had 64 coins to Dave's 32
They both gave 24 away
leaving Seamus with 40 coins and Dave with 8
Seamus has twice as many coins as dave, and now has 5 times as many
2007-11-04 23:21:24 · answer #4 · answered by mark 7 · 1⤊ 0⤋
Let s = Seamus' gold coins
d = Davey gold coins
.
s = 2d
or d = 1/2*s
After they give their coins to H,
s -24 = 5*( d - 24)
or
s - 24 = 5d - 120
or
s - 24 = 2.5*s - 120
or
-1.5 *s = -96
Therefore
s = 64
And d = 32
Check it out:
S starts with 64, and D starts with 32
Both give 24 to H, so S is left with 40 and D is left with 8
40 = 5 X 8
So
S ends up with 5 times D.
2007-11-04 23:27:17 · answer #5 · answered by Joe L 5 · 1⤊ 0⤋
x = coins of Davey
2x = coins of Seamus
2x - 24 = 5(x - 24)
2x - 24 = 5x - 120
3x = 120 - 24 = 96
x = 32 -- coins of Davey
2x = 64 -- coins of Seamus
2007-11-04 23:20:09 · answer #6 · answered by Anonymous · 2⤊ 0⤋
Seamus=2G, Davey=G
Horatio=24+24=48.
seamus=2G-24, Davey=G-24
2G-24=5(G-24), 2G-24=5G-120
G==32
Seamus = 2G = 64
2007-11-05 03:50:40 · answer #7 · answered by nike s 2 · 0⤊ 0⤋
suppose ,
Seamus = a
Davey = b
Horatio = c
So
a = 2b
and
a-24 = 5(b-24)
a-24 = 5b-120
2b-24 = 5b-120
3b = 96 => b=32
a=64
means the start Seamus have 64 gold coins
2007-11-04 23:17:46 · answer #8 · answered by Anonymous · 2⤊ 0⤋
seamus had 120 gold coins whilst davey only had 60. am i right.
2007-11-04 23:17:51 · answer #9 · answered by Ladydeath 1 · 0⤊ 1⤋
64
2007-11-04 23:17:05 · answer #10 · answered by Anonymous · 1⤊ 0⤋