2007-11-04 18:56:10 · 19 answers · asked by Anonymous in Science & Mathematics ➔ Physics
no
Because the energy in the collision is shared between the two vehicles.
As opposed to the one hitting the wall which transfers all the energy back to the car.
if you think of the kinetic energy:
in first instance each car has 0.5m30^2 = 450m
a total of 900m - shared equally (unless one is a 4x4 and the other a mini)
in the second case
0.5m60^2 = 1800m
give me a head on crash with another car anyday
2007-11-04 19:33:35 · answer #1 · answered by Anonymous · 4⤊ 0⤋
The majority is wrong. It is NO!
Case 1. Car A is going at 30 mph. It runs into Car B going 30 the opposite direction. Afterwards, it is stopped. That's 30 to 0.
Case 2. Car A is going 60 mph and runs into a wall. That's a deceleration of 60 to 0. Lot more damage to Car A. It will have disipated 4 times as much energy in the impact. Ouch!!
2007-11-08 11:12:40 · answer #2 · answered by Frst Grade Rocks! Ω 7 · 0⤊ 0⤋
If the cars are traveling in the same direction, let's say towards the positive x-axis, and the cars+the still object are all identical (meaning they have the same mass, volume, shape etc.), then the answer would be yes.
The justification of this can be made by calculating the momenta of the two systems. The inital momentum equals the final momentum, and from there on you can simply calculate from the Pinital = Pfinal equation. If you do the algebra right, you will see the two systems' velocities are the same.
2007-11-05 05:01:34 · answer #3 · answered by Anonymous · 0⤊ 1⤋
In theory you are right. However cars particularly are built with what is called Crumple Zones. This enables the car to crumple up and effectively slow the speed of impact. For all practical purposes the relative velocity of the 2 cars is 60 mph and the effect would be like hitting a wall.
2007-11-04 19:57:55 · answer #4 · answered by ANF 7 · 1⤊ 3⤋
No. Assume all of the kinetic energy goes into mangling up the cars. Now calculate the total kinetic energy in each scenario.
2007-11-04 19:05:25 · answer #5 · answered by Pete WG 4 · 1⤊ 0⤋
A) In thought they could want again to an entire end yet momentum and how they deform randomly regularly outcomes on them rotating around one yet another on the ingredient of impression. 2) mixed collision velocity certainly would be 120mph.
2016-10-15 02:19:03 · answer #6 · answered by ? 4 · 0⤊ 0⤋
yes. because the force of inpact betwen the 2 cars colliding will have the impact of 60mph.
2007-11-05 00:05:27 · answer #7 · answered by Anonymous · 0⤊ 1⤋
The closing speed is exactly the same but a wall is a wall and another car is another car. I.e a wall will not deform like hitting another car.
xxR
2007-11-04 19:07:05 · answer #8 · answered by Anonymous · 2⤊ 2⤋
Only if they were travelling in exactly the opposite direction to each other.
If they were both travelling side by side in the same direction and bumped into the side of each other, the impact speed would be much lower.
2007-11-04 19:02:15 · answer #9 · answered by David P 7 · 0⤊ 3⤋
lets answer this problem in different frames:
frame 1: observers on car A and car B
from car A the driver see that car B is coming with 60MPH(from relative velocity Vab=Va-Vb=30-(-30)=60MPH)
towards him so here he thinks that car B will hit it with speed 60MPH.same is the case for driver in car B
frame 2:observer on ground
for observer on ground velocity of car A is Vag= 30MPH
for observer on ground velocity of car B is Vbg= -30MPH
so Vab=Vag-Vbg=30-(-30)=60MPH
so hee see that car A hits car B with 60MPH
same is the case for car B
2007-11-04 19:13:26 · answer #10 · answered by bhanu p 2 · 0⤊ 4⤋