Negative exponents, quick question please help?? URGENT!!!!?

Question

How do I simplify this

a^-1 + b^-2 / a^-2 + b^-1

a to the -1 power plus b to the -2 power all divided by a to the -2 power plus b to the -1

Answer 1

a(a+b^2) / b (a^2 + b)

Answer 2

(1/a + 1/b^2) / (1/a^2 + 1/b) to get rid of the negative exponents

then multiply by a^2*b^2 / a^2*b^2 to get rid of the denominators in the fractions - gives
(ab^2 + a^2) / b^2 + a^2 * b

then simplify further

a (b^2+a) / b(b + a^2)

Answer 3

a/b

put the a^-2 on the top of the equation and simplify to a^1

put the b^-2 on the bottom of the equation and simplify to b^1

Answer 4

Simplified: ((1/a) + (1/b^2)) / ((1/a^2) + (1/b))

Now find common denominator:

( (b^2 +a) / (ab^2) ) / ((b+a^2)/(a^2b))

Flip bottom equation , multiply and simplify:

( (b^2 + a) / (ab^2) ) x (( a^2b)/(b+a^2))

ab is a common factor. They cancel.

((b^2 + a) / b x (a/(b+a^2))

(ab^2 + a^2) / (b^2 +a^2b)

This is the simplest it can get w/o unnecessary factoring.

Answer 5

[a(a+b^2)] / [(a^2+b)b] < that is the most u can simplify this basically changed the negative exponents in to positive