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x^4+2x^2-2x=

2007-11-04 14:55:00 · 4 answers · asked by o0o 1 in Science & Mathematics Mathematics

4 answers

random choice of x value of 1
(x^4+2x^2)-2x=?
(1^4 +2^2)-2=
(1+8)-2=
9-2=7

2007-11-04 15:17:37 · answer #1 · answered by aprilmacfadden 3 · 0 3

x^4+2x^2 - 2x

= x (x^3+2x-2)

Because the remaining part is a cubic equation, quadratic equation won't solve the problem.

x (x^3+2x-2) is the farthest you can go with simplifying this problem.

2007-11-04 15:14:13 · answer #2 · answered by Andy L 2 · 0 0

x^4 + 2x^2 - 2x =
x(x^3 + 2x - 2)
There are two "real" roots and two complex roots.
The real roots are
x = 0
x ≈ 0.7709169975
(found numerically by spreadsheet)
The complex roots can be found by dividing
x^3 + 2x - 2 by x - 0.7709169975 and solving the resulting quadratic by quadratic equation or completing the square.
Other methods for finding the roots of the cubic are presented here:
http://en.wikipedia.org/wiki/Cubic_equation

2007-11-04 16:58:52 · answer #3 · answered by Helmut 7 · 0 0

x^4+2x^2-2x=(x)(x^3+2x-2)

no better answer

2007-11-04 15:05:32 · answer #4 · answered by Amy W 6 · 0 0

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