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3x + 12 = 6
subtract 3x to get x by its self
x + 9 = 6
then I subtract 9 from six and get 3 But when I go and check my answer it is wrong can someone tell me what I am doing wrong.

2007-11-04 14:46:01 · 14 answers · asked by m&m 1 in Science & Mathematics Mathematics

14 answers

3(x + 4) = 6
3x + 12 = 6

"subtract 3x to get x by its self"
No, you subtracted 2x+3 from the LHS and nothing from the RHS.

To get x by itself, you should subtract the constant term on the LHS, 12, from both sides:

3x + 12-12 = 6-12
3x = -6

Now to get from 3x to x, you must *divide* by 3 (not subtracting):
3x/3 = -6/3
x = -2 [SOLUTION]

2007-11-04 14:49:08 · answer #1 · answered by smci 7 · 0 0

You can't subtract 3x from 12....Here's what you should do
3x + 12 = 6

subtract 12 from both sides
(3x+12) - 12 = (6) - 12
giving,
3x = -6
then divide by 3 giving you
x= -2

2007-11-04 22:53:58 · answer #2 · answered by Anonymous · 0 0

3(x + 4) = 6 MULTIPLY the 3 through the parenthesis
3x + 12 = 6 SUBTRACT 12 from both sides
3x = 6 - 12
3x = -6 DIVIDE both sides by 3
x = -6/3
x = -2 ANSWER

CHECK by substitutin x = -2 back into the original equation
3(x + 4) = 6
3(-2 + 4) = 6
3 (2) = 6
6 = 6 it checks out

2007-11-04 22:51:13 · answer #3 · answered by r r 5 · 1 0

That isn't how it works... You can't subtract the 3x because it was multiplied, not added. Here is the correct way:

3(x+4)=6
-divide both sides by 3
x+4=2
-subract 4 from both sides
x=-2

You could also multiply the 3 through like you started:
3x+12=6
-subtract 12 from both sides
3x=-6
-divide by 3
x=-2

2007-11-04 22:56:07 · answer #4 · answered by Lauren 3 · 0 0

You cannot subtract 3x to get x. You can only subtract Xs with Xs and numbers with numbers.
What you need to do is
3x + 12 = 6
Subtract 12 both sides to get
3x = -6
then divide by 3 to get
x = -2

2007-11-04 22:50:25 · answer #5 · answered by Aeons 2 · 0 0

3x + 12 = 6
=> 3x = 6 - 12 = -6
=> x = - 2

[ 3x + 12 = 6
subtract 3x to get x by its self
x + 9 = 6
If you subtract 3x from both sides, you get 12 = 6 - 3x and not x + 9 = 6. Moreover, it is a meanless step.]

2007-11-04 22:50:16 · answer #6 · answered by Madhukar 7 · 0 0

3*x + 3*4 = 6
3x + 12 = 6
3x + 12 - 12 = 6 - 12
3x + 0 = - 6
3x / 3 = -6 / 3
x = -2
For check
3( -2 + 4) = 6
-6 + 12 = 6
6 = 6
So x = -2 is correct
About what you do wrong ??
well it is you subtract unkown with known which means
3x - 3 and this is can not be equal to x
to get rid of what comes with unkown is allways (divide)
3x / 3 = x

2007-11-05 09:32:32 · answer #7 · answered by Rayan Ghazi Ahmed 4 · 0 0

3x+ 12 = 6
Subtract 12 from both sides
3x = -6
Divide by 3
x = -2

check:
3(-2+4) = 6
3(2) = 6
6 = 6

2007-11-04 22:50:37 · answer #8 · answered by Ms. Exxclusive 5 · 0 0

3x+12=6
3x= -12+6
3x= -6
then divide by 3
x= -2

2007-11-04 22:59:34 · answer #9 · answered by sunshine.hizon 2 · 0 0

Here's another way to look at it:

3(x+4) = 6
x+4 = 2
x= -2

As for the way you are doing it:

3(x+4) =6
3x +12 =6
3x = -6
x = -2

That's the great thing about algebra - if doesn't matter which path you take, as long as you stick to the rules.

2007-11-04 22:54:08 · answer #10 · answered by rckrllrfg 2 · 0 0

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