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Find the tangent line to the graph y=20+5x^2-17x at the point (3,14). The equation y=____x+ ____ is the desired tangent line

2007-11-04 14:42:31 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

y' = 10x - 17 = 30-17 = 13 at (3, 14)
y = 13(x-3) + 14 = 13x - 25

2007-11-04 14:58:17 · answer #1 · answered by sahsjing 7 · 0 0

take the 1st by-product and set it equivalent to 0, then sparkling up this for x, which provides an x fee on the tangent line; plug this fee decrease back into the unique equation to acquire a corresponding y fee. Now you have this element and additionally the element (3, 14), and using those 2 factors, you may confirm a numerical fee for the slope. after that, use element-slope variety with the element (3,14) to confirm the equation by way of that element.

2016-11-10 07:23:04 · answer #2 · answered by ross 4 · 0 0

f `(x) = 10x - 17
f `(3) = 30 - 17
f `(3) = 13
m = 13
y - 14 = 13(x - 3)
y = 13x - 39 + 14
y = 13x - 25

2007-11-04 19:04:10 · answer #3 · answered by Como 7 · 0 1

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