How do I solve this radical equation?

1 ⤊

Here's the equation:

sqrt(b^2 - 5b -14) = b + 11

How do I solve this? Thanks for your help!!!

2007-11-04 14:38:29 · 2 answers · asked by DoWHATiDO 3 in Science & Mathematics ➔ Mathematics

Square both sides:
b^2 - 5b - 14 = (b + 11)^2
b^2 - 5b - 14 = b^2 + 22b + 121
27b = -135
b = -5

2007-11-04 14:45:37 · answer #1 · answered by Aeons 2 · 1⤊ 0⤋

bÂ² - 5b - 14 = bÂ² + 22b + 121
- 135 = 27 b
b = - 5

2007-11-04 19:58:53 · answer #2 · answered by Como 7 · 0⤊ 1⤋