Find the inverse function of f...?

Question

y= (1+3x) / (5-2x)


How to do it..??

Answer 1

switch x and y and solve for y

x = (1+3y)/(5-2y)
5x - 2xy = 1 + 3y
(3+2x)y = 5x - 1
y = (5x-1)/(3+2x)

Answer 2

y= (1+3x) / (5-2x)
To find inverse switch x and y, and solve for y
x = (1+3y) / (5-2y)
x(5 - 2y) = 1 + 3y
5x - 2xy = 1 + 3y
2xy + 3y = 5x - 1
y(2x + 3) = 5x - 1
y = (5x - 1)/(2x + 3)
Hence inverse function f'(x) = (5x - 1)/(2x + 3)

Answer 3

y= (1+3x) / (5-2x)
y(5-2x)=(1+3x)
5y-2xy=1+3x
5y-1=x(3+2y)
x=(5y-1)/(2y+3)
Therefore inverse function is
y=(5x-1)/(2x+3)