Can someone teach me how to do this chem problem?

Question

The equilibrium constant (Kc) for the reaction
2HCl(g)<===>H2(g) + Cl2(g)
is 4.17x10^-34 at 25 C. What is the equilibrium constant for the reaction
H2(g) + Cl2(g) <===> 2HCl(g)
at the same temperature?

Answer 1

since K1=[products1] / [reactants1]

since it is the reverse reaction

K2=[reactants1]/[products1] =1/K1

so take the reciprical of K
1 / 4.17x10^-34

Answer 2

this question is not that bad - when you reverse the direction of a reaction, the equilibrium constant becomes the reciprocal of the original equilibrium value, so the K for the second equation is 1 / 4.17e-34 = 2.40e33

Answer 3

K1 = [H2][Cl2] / [HCl] ^2

K2 = [HCl]^2 / [H2][Cl2]

Notice that K2 is the reciprical of K1. Likewise the value of K2 is simply the reciprocal of K1.

K2 = 1.00 / (4.17 Exp -34) = 2.40 Exp +33

Answer 4

It would be the reciprocal.

The 2 equations are the same reversible reaction.