2007-11-04 13:21:48 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Astronomy & Space
Increase. If the distance is cut in half the force of gravity gets 4 times stronger. This is the famous inverse square relationship.
2007-11-04 13:27:11 · answer #1 · answered by campbelp2002 7 · 3⤊ 0⤋
The force of gravity is inversely proportional to the square of the distance.
So if 2 objects were 3 times closer, the gravity between them would be 9 times greater.
And if the 2 objects were 4 times farther, the gravity between them would be 1/16th as strong.
2007-11-04 14:22:04 · answer #2 · answered by Anonymous · 1⤊ 0⤋
F = kQq/r^2, that's, the rigidity between 2 charged debris is proportional to the made of the charges of the two debris, Q and q, and inversely proportional to the sq. of the area between them. there is not any electric rigidity between a charged and uncharged particle or between 2 uncharged debris. in the metric equipment, expenditures Q and q are given in "coulombs", d is in meters, and ok is approximately equivalent to 9.0 x 10^9 N • m^2 / C^2 in case you double the area between 2 charged debris, and the charges stay consistent, the rigidity will become one fourth of what it became into. Triple the area and the rigidity will become one million/9 of what it became into. Halve the area, and the rigidity doubles. Make the area one 0.33 of what it became into, and the rigidity will become 9 situations what it became into.
2017-01-04 22:16:32 · answer #3 · answered by ? 3 · 0⤊ 0⤋
Gravity, of course, would increase as the distance decreased.
2007-11-04 13:24:59 · answer #4 · answered by Nighthawke 5 · 0⤊ 0⤋
Gravitational pull will become stronger
2007-11-04 13:35:21 · answer #5 · answered by 2447 3 · 0⤊ 0⤋