formula: S=L-rL
Solve for r in the formula above
2007-11-04 12:47:23 · 7 answers · asked by jennifer 1 in Science & Mathematics ➔ Mathematics
S = (1-r)L
S/L = 1-r
r = 1 -S/L
2007-11-04 12:51:03 · answer #1 · answered by David F 5 · 0⤊ 0⤋
If S=L-rL, then we want to eliminate all the variables on the side that contains r, right? Well upon looking at the problem, I see that we have L's in both of those Right Hand terms, so I'd probably start by factoring those out. So basically:
S = L-rL
S = L(1-r)
We can go ahead and divide by that L, leaving:
S = L(1-r)
S/L = 1-r
And now all that's left is to do the last few steps:
S/L = 1-r
S/L - 1 = -r
-S/L + 1 = r, or
r = 1 - S/L
Does that make sense?
2007-11-04 12:53:03 · answer #2 · answered by twigg1313 3 · 0⤊ 0⤋
S = L - rL
- L
(L-S = -r L) / -L
L-S/L= r
2007-11-04 12:51:55 · answer #3 · answered by specimenq5 2 · 0⤊ 0⤋
s = L - rL
rL = L - S
rL/L = (L - S)/L
r = (L - S)/L
2007-11-04 22:41:22 · answer #4 · answered by Derrick James D 1 · 0⤊ 0⤋
not that difficult
S-L= -rL
(S-L)/L = -r
-((S-L)/L)) = r
2007-11-04 12:54:19 · answer #5 · answered by tigerbaby76 5 · 0⤊ 0⤋
r = (L - S)/L
2007-11-04 12:51:42 · answer #6 · answered by Matthew 1 · 0⤊ 0⤋
r=(L-S)/L
2007-11-04 12:51:54 · answer #7 · answered by norman 7 · 0⤊ 0⤋