I need help with this problem.
Arrange the following according to expected values for b (volume correction value) in van der Waal's equation.
He, CO2, H2O, HF, SF6
2007-11-04 12:37:43 · 3 answers · asked by Craig S 2 in Science & Mathematics ➔ Chemistry
SF6 > CO2 > H2O > HF > He
2007-11-04 12:43:06 · answer #1 · answered by steve_geo1 7 · 0⤊ 0⤋
Think of the volume correction with respect to how big or small the molecule is. Using this criterion, smallest b value will be Helium and largest will be SF6. Thus, the order is
He < water < or close to HF < CO2 < SF6.
2007-11-04 13:05:18 · answer #2 · answered by Aldo 5 · 0⤊ 0⤋
that's extremely direct question. purely use the two formula to sparkling up it. to study Van der Waals equation, i think of it a minimum of opt for a point or larger. so if it won't confusing so which you would be able to plug in the fee
2016-11-10 07:05:34 · answer #3 · answered by Anonymous · 0⤊ 0⤋