2007-11-04 12:31:15 · 6 answers · asked by abraymond5 1 in Science & Mathematics ➔ Mathematics
y(y^2-12y+36) = y(y-6)^2
2007-11-04 12:34:37 · answer #1 · answered by norman 7 · 0⤊ 0⤋
y^3 – 12y^2 + 36y
= y(y^2-12y +6)
= y(y-6)^2
2007-11-04 12:35:47 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
y3-12y2+36y y (y2-12y+36) y (y-6) (y-6)* first take out the applicable uncomplicated factor that's y and you get the expression listed in line 2, then you certainly factor the expression in line 2 and you recieve your answer in line 3.
2016-11-10 07:03:30 · answer #3 · answered by cauley 4 · 0⤊ 0⤋
y^3 – 12y^2 + 36y
factor out a y
y(y^2-12y+36)
y(y-6)(y-6)
y=0 | y-6=0 | y-6=0
+6 +6 +6 +6
-----------------
y= 6 y=6
y=0, 6
2007-11-04 13:03:23 · answer #4 · answered by katie99_2006 1 · 0⤊ 0⤋
Factor out a y to start.
y(y^2-12y+36)
Factor this new expression.
y(y-6)(y-6)
2007-11-04 12:35:44 · answer #5 · answered by Matt 3 · 0⤊ 0⤋
y(y^2 - 12y + 36)
y(y-6)(y-6)
2007-11-04 12:34:41 · answer #6 · answered by Ms. Exxclusive 5 · 0⤊ 0⤋