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Find the domain:

1) 1 / (x^3 + 25)

2) 1 / (x^3 - 25)

2007-11-04 12:26:58 · 2 answers · asked by Ashke 1 in Science & Mathematics Mathematics

2 answers

in both questions you need the denominator to be different from 0
so
1) x^3 + 25 =0
x=-cube root 25
2) x^3 -25 =0
x = cube root 25

2007-11-12 06:43:48 · answer #1 · answered by Anonymous · 0 0

1) all real # but not (-25)^(1/3)
2) all real # but not (25)^(1/3)

it can never be #/zero

2007-11-04 12:35:37 · answer #2 · answered by info2know 3 · 0 0

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