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2x+5y= -4.......(1)
3x-y=11
-y=11-3x
y=3x-11.....(2)
Substituting y by 3x-11 in (1)
2x+5(3x-11)= -4
2x+15x-55= -4
17x= -4+55=51
x=51/17=3
Plugging x in(2)
y=3*3-11= -2
2007-11-04 12:21:13
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answer #1
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answered by alpha 7
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Thanks for a very simple question. Follow my step below.
Firstly, given the equation:
2x + 5y = -4
3x - y = 11
Mark as (1) and (2):
2x + 5y = -4.....(1)
3x - y = 11.....(2)
From equation (2), we find y:
3x - y = 11
-y = 11 - 3x
y = 3x - 11.....(3)
Then, we substitute (3) into equation (1):
2x + 5y = -4
2x + 5(3x - 11) = -4
2x + 15x - 55 = -4
17x - 55 = -4
17x = -4 + 55
17x = 51
x = 51 ÷ 17
x = 3
Next, substitute x = 3 into equation (3):
y = 3x - 11
y = 3(3) - 11
y = 9 - 11
y = -2
Therefore, the answer should be:
x = 3 and y = -2
I hope you got the best answer for your question. Have a nice day!
2007-11-04 12:27:04
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answer #2
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answered by Nizam89 3
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The point of the substitution method is to take a complicated system and substitue something not so complicated into the system.
Given the two systems, you assume that the same values for x and y will work in both systems.
The second statement is the simplest form. With a coefficient of -1y, manipulate the statement to get a positive y alone on one side:
add -11 and y to both sides. Simplify to get 3X - 11 = y
Substitue (3x -11) for y in the first statement so that you have:
2x +5(3x-11) = (-4)
Multiply through and Solve for X, then find Y by substituting the known value for X.
2007-11-04 12:25:47
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answer #3
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answered by Anonymous
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Isolate one of the variables in either equation. In this case, the easiest to isolate will be the y in the second equation.
Add y to both sides and subtract 11 from both sides to get:
3x - 11 = y
In the first equation, everywhere you see a y, substitute in a 3x-11. You get:
2x + 5(3x-11)= -4
2x + 15x - 55 = -4
17x = 51
x = 3
In the second equation, everywhere you see an x, substitute a 3 to get:
3*3 - y = 11
9 - 11 = y
-2 = y
2007-11-04 12:19:28
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answer #4
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answered by Bob G 6
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Okay, to make this easier, set y=3x-11:
3x-y=11
3x=y+11
3x-11=y
Then substitute 3x-11 in for 2x+5y=-4:
2x+5(3x-11)=-4
Distribute:
2x+15x-55=-4
Simplify:
17x-55=-4
Add 55 over to the other side:
17x=55-4
17x=51
Divide:
17x=51
x=3
Substitute 3 into the original problem:
3(3)-y=11
9-y=11
Subtract 9 onto the opposite side:
-y=11(-9)
-y=2
Divide by -1 on both sides to make y positive:
y=-2
2007-11-04 12:21:50
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answer #5
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answered by crazyanimeluva 1
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Rearrange the second equation to 3x-11=y.
THen subsitute the left side of the equation into 2x+5(3x-11)= -4.
2007-11-04 12:16:59
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answer #6
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answered by L B 4
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y = 3x - 11
2x + 15x - 55 = - 4
17x = 51
x = 3
9 - y = 11
y = - 2
x = 3 , y = - 2
2007-11-04 22:01:07
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answer #7
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answered by Como 7
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