How do you do this kind of math problem?

Question

Find a quadratic equation for which the solutions are 3 and 5

I cant figure out how to do it :/

OH! thanks everyone... i couldnt figure out where to plug in 3 and 5

Answer 1

[04]
A quadratic equation having solution of 3 and 5,will be in the following format
x^2-(3+5)x+(3)(5)
=x^2-8x+15

Answer 2

A. X=3 → X-3 = 0

B. X=5 → X-5 = 0

Multiply equations A & B

→ (x-3)(X-5)=0

Your equation gained by expanding the above multiplication

X^2 -8X +15 =0

Answer 3

Simple.

Given the solutions are 3 and 5, means that the roots are 3 and 5.

In other words, x = 3 or x = 5.

Once you got that, you should know that the factors of the quadratic equation are (x - 3) and (x - 5).

Then multiply the two factors together to find the quadratic equation.

(x - 3)(x - 5) = x^2 - 8x + 15

Answer 4

A quadratic equation has x^2 in it.

(x - 3) (x - 5) = 0
[because then the answers would be 3 and 5]

x^2 -5x -3x + 15 = 0
[multiplied out]

x^2 -8x + 15 = 0
[added together, your answer]

Answer 5

x = 3; x = 5
implies (x-3)(x-5) = 0
multiplying out:
x^2 -3x -5x +15 = 0
x^2 -8x +15 = 0

ANS: x^2 -8x +15 = 0

Answer 6

write this
(x-3)(x-5) = 0
which becomes x^2 - 8x + 15 = 0

Answer 7

therfore your equation must be
(x - 3)(x - 5) = 0
x^2 - 8x + 15 = 0

Answer 8

= (x -3 ) (x -5) = x^2 - 8x +15

Answer 9

let x1=3
x2=5
if x1 and x2 are the solutions(roots) of a quadratic equation, then the quadratic equation is

x^2-(sum of roots)x+(product of roots)=0
x^2-(x1+x2)x+(x1*x2)=0
x^2-8x+15=0 is the answer.

Answer 10

(x-3)(x-5) = 0
x^2 - 8x + 15 = 0 is the eq you want