a telephone plan is $35 for 400 minutes and $4.00 a mintue per extra minute. Mary uses 600 that month. Write a piecewise function.
thanks!
2007-11-04 09:22:28 · 6 answers · asked by name has been deleted 1 in Science & Mathematics ➔ Mathematics
a telephone plan is $35 for 400 minutes:
f(x) = $35, x <= 400
and $4.00 a minute per extra minute (over 400):
f(x) = $35 + $4(x - 400), x > 400
Mary uses 600 that month:
f(600) = $35 + $4(600 - 400) = $35 + $4(200) = $835
Wow, that's an expensive phone plan.
2007-11-04 09:39:34 · answer #1 · answered by Jim Burnell 6 · 1⤊ 0⤋
This function has two parts 1st $35 for 400 minutes and second $4.00 a mintue per extra minute. So all you have to do is start the function at $35 for 400 minutes but use the equation of the second part. call x axis minutes and y axis $
second equation has a slope of 4
y-35=4(x-400) for x>400
f(x)= {4(x-400)+35 for x>400
{35 for x is less than or equal to 400
Now plug in 600 for x
4(600-400)+35=$835
2007-11-04 09:39:05 · answer #2 · answered by gang$tahtooth 5 · 0⤊ 0⤋
You don't really need a piecewise function for that. A formula for the solution would be:
35+(600-400)x4
2007-11-04 09:36:53 · answer #3 · answered by dustin_barr 4 · 0⤊ 0⤋
C = 35 (t C = 35 + 4t (t>400)
2007-11-04 09:35:23 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
total minutes will be 835.
400minutes for $35
and after that per minutes is $4 so 200 minutes are extra so 200*4=800. so 35+800= 835.
2007-11-04 09:42:05 · answer #5 · answered by chem-mystry 2 · 0⤊ 0⤋
x+y=400
35x+4y=600
2007-11-04 09:36:15 · answer #6 · answered by Anonymous · 0⤊ 1⤋