if the hypotenuse of a right triangle is 12ft and a side is 6ft what is the length of the other side express your answer in radical form?
2007-11-04 08:12:54 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
12 ² = x ² + 6 ²
x ² = 12 ² - 6 ²
x ² = (12 - 6) (12 + 6)
x ² = 6 x 18
x ² = 108
x ² = 36 x 3
x = 6 √3 ft
2007-11-04 10:41:49 · answer #1 · answered by Como 7 · 2⤊ 1⤋
If a and b are two sides of a right angle triangle and c is the hypotenuse, then
c^2 = a^2 + b^2
Hence
b^2 = c^2 - a^2
In your case
b^2 = 12^2 - 6^2
b^2 = 144 -36
b^2 = 108
b = sqrt(108)
b= 6*sqrt(3)
2007-11-04 16:24:31 · answer #2 · answered by Michael G 3 · 0⤊ 1⤋
The Pythagorean Theorem
a^2 + b^2 = c^2
c is the hypotenuse
6^2 + b^2 = 12^2
b^2 = 144 - 36
b^2 = 108
b = sqrt(108)
to simplify the square root:
b = sqrt(2 * 2 * 3 * 3 * 3)
b = 2* 3 sqrt(3)
b = 6sqrt(3)
2007-11-04 16:21:42 · answer #3 · answered by RoboPaul 3 · 0⤊ 0⤋
(12 x 12) - (6 x6) = 144 - 36
= 108
Now find the square root of 108 to give length of unknown
approx 10.4
2007-11-04 16:20:50 · answer #4 · answered by John S2005 3 · 0⤊ 0⤋
12^2 - 6^2 = c^2
144 - 36 = c^2
108 = c^2
c = sqrt(108)
2007-11-04 16:19:37 · answer #5 · answered by Anonymous · 0⤊ 0⤋
a*a + b*b = c*c
a*a + 36 = 144
a*a = 144-36 = 108
a = 6*sqrt3
2007-11-04 16:19:18 · answer #6 · answered by John F 1 · 0⤊ 0⤋