Altitudes of a triangle??

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Altitudes of a triangle??

find the equation of the altitude from A to BC
A(11,12)
B(7,2)
C(13,-6)

2007-11-04 07:55:17 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

3 answers

Slope BC = -8/6= -4/3
So slope of altitude = 3/4
y = 3x/4 +b
12 = 33/4 +b
b = 48/4 -33/4 = 15/4
So equation of altitude is y= 3x/4 +15/4,or
4y = 3x+15

2007-11-04 08:02:29 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋

slope of BC=DY/DX = 8/-6=-4/3
slope of altitude from A to BC=3/4
Eq. of the altitude from Ais:
y-12=3/4)(x-11).
4y-48=3x-33
3x-4y+15=0.ANS.

2007-11-04 16:03:51 · answer #2 · answered by Anonymous · 0⤊ 0⤋

you find the midpoint of bc. so 7+13/2, 2+-6/2 equals 10, -2 and you draw a line from point A to that point.

2007-11-04 16:03:34 · answer #3 · answered by amberpearl92 2 · 0⤊ 0⤋