what is the line through (4,0) that is perpendicular to the line x + y = 3?

Answer 1

that equatin is the same as
y = -x + 3

make opp recipricol for perp. then u have
y = 1/2x + 3... but it has to go through (4, 0) so put it into the equation:

0 = 1/2(4) + b
0 = 2 + b
b = -2

so ur equation is
y = 1/2x - 2

Answer 2

Let the equation of the line be given by y = mx + b
The other line x+ y = 3, can be written as
y = -x + 3
Perpendicular to this line the slope will be the negative reciprocal: so m = -(1/[-1]) = 1
Now we have
y = (1)x + b, but it has to go thru (4,0) so
y(4) = (4) + b = 0
and b = 0-4 = -4, finally
y = x-4

Answer 3

To get a line that is perpendicular to the given line, swap the coefficients of x and y and change the sign of one of them. It doesn't matter which one. So the line will be of the form:

x - y = c

The equation of the perpendicular line thru the given point (4,0) is:

(x - 4) - (y - 0) = 0
x - y = 4

Answer 4

y=x-4

Answer 5

solve for y: y=-x+3
inverse slope: y=x+3
put in points for x and y: 0=4+b (b=y-intercept)
solve for b: -4=b
create the equation: ********** y=x-4********