Given f(x) = -x to the third power, + x to the second power, +3x +4, find f(-1), f(0), and f(1)?

Answer 1

-(-1)^3+(-1)^2+3(-1)+4=?
-(0)^3+(0)^2+3(0)+4=?
-(1)^3+(1)^2+3(1)4=?

Answer 2

if f(x)= -x^3 + x^2 + 3x + 4, then to find f(-1), f(0), and f(1), you just plug the numbers in for x.

So.

f(-1) = -(-1)^3 + (-1)^2 + 3(-1) + 4 = -(-1) + 1 -3 + 4 = 3
f(0) = -(0)^3 + (0)^2 + 3(0) + 4 = 0 + 0 + 0 + 4 = 4
f(1) = -(1)^3 + (1)^2 + 3(1) + 4 = -1 + 1 + 3 + 4 = 7

If you have a graphing calculator, you can also plug the original function [(-x^3) + (x^2) + 3x + 4] into your y equals (press y= at the top of the calculator). Then press 2nd, then the button at the top that says graph to open up your table. Where x = -1, there will be your y value (3). Same for x= 0 and x = 1

Answer 3

f(x) = -x^3 +x^2 +3x+4
f(-1) = -(-1) +1 -3 +4 = 3
f(0) = 4
f(1) = -1+1+3+4= 7