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i'm having a lot of trouble graphing this!
i know the vertex is (10, 1) since it follow the y=a|x-h| +k formula but i dont know how to find two other points to use to make my graph.
when i tried substituting to find the y intercept i got this :
y= 2 | 2 x 0 + 10| +1
y = 2 |10| +1
y= 21
is this right?
if so, when i tried substituting to find what y would be if the x=6, i got y= 45.
this doesnt make sense when i grpah it because my graph goes up then down.
can someone explain to me how to find two points?

2007-11-04 05:56:20 · 3 answers · asked by 2 in Science & Mathematics Mathematics

and then how do i write a function in the form y= a|x-h|+k that has the same graph?

2007-11-04 05:58:16 · update #1

3 answers

y=4x+20 +1
y=4x+21

2007-11-04 06:03:59 · answer #1 · answered by Janie333 2 · 0 0

pick any points you want. Try it on a graphing calculator. You can pick any x values you want then solve. This is going to look like a V. The value (6,45) is correct

2007-11-04 06:05:25 · answer #2 · answered by roguetrader12002 4 · 0 0

This is not one straight line

You got one point already (0,21)

The lowest point is when |2x+10| = 0 x=-5 (-5,1)

joint these two point and you have a line with positive slope

Use x = -10, say and find another point (-10,21)
then joint (-5,1) and (-10,21) gives a straight like with a negative slope.

2007-11-04 06:06:10 · answer #3 · answered by norman 7 · 0 0

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