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2007-11-04 05:55:28 · 4 answers · asked by haj a 1 in Science & Mathematics Mathematics

4 answers

The amplitude is 3

2007-11-04 05:59:37 · answer #1 · answered by Anonymous · 0 0

The best amplitude is F(x)=3 when x=0

2007-11-04 14:08:02 · answer #2 · answered by sprintaco 1 · 0 0

Try to write it as A cos (2x+t) = Acos 2x cos t-Asin2x sin t
A cos t =3
A sin t = 3
squaring and sum
A^2 =18 so A = amplitude = sqrt(18) = 3*sqrt(2)

2007-11-04 14:08:44 · answer #3 · answered by santmann2002 7 · 0 0

To find the maximum value, differentiate the equation (with respect to x). This gives
dy/dx = -6sin(2x) - 6cos(2x)
then equate this to zero. This occurs when
-6sin(2x) = 6cos(2x)
i.e. when 2x = 315 degrees.
Sin(315) = -1/sqrt(2)
Cos(315) = 1/sqrt(2)
Hence
y = 3/sqrt(2) + 3/sqrt(2)
= 6/sqrt(2) = 4.24264

2007-11-04 14:40:28 · answer #4 · answered by Michael G 3 · 0 0

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