Solving the following equation for the variable Y?

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Solving the following equation for the variable Y?

x^3y^2=t^4/w

2007-11-04 04:43:19 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

4 answers

x^3y^2=t^4/w
y^2 = t^4/(wx^3)
y = +/- t^2/x sqrt(1/wx)

2007-11-04 04:48:52 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋

sparkling up for y in considered one of your equations then substitue for y in the different equation like this y=17-5x then plug into 6x+3y=24 so which you get 6x + 3(17-5x)=24 sparkling up for x 6x + fifty one- 15x=24 -9x + fifty one=24 -9x=-27 x= 3 plug x decrease back into 6x +3y=24 6(3) + 3y =24 18 + 3y = 24 3y=6 y =2 so your x,y is (3,2)

2016-11-10 06:12:51 · answer #2 · answered by ritzer 4 · 0⤊ 0⤋

y= sqrt of t^4/ x^3 w

2007-11-04 04:48:59 · answer #3 · answered by Riza m 3 · 0⤊ 0⤋

y = (t^4/x^3w)^1/2

2007-11-04 04:47:36 · answer #4 · answered by Anonymous · 0⤊ 0⤋