2007-11-04 02:37:31 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
It is already factored.
(3x - 4)(2x - 7) = 0
x = 4/3 , x = 7/2
2007-11-04 04:25:28 · answer #1 · answered by Como 7 · 1⤊ 1⤋
Your problem is already in factored form.
Apply the zero product property: (set each differect factor equal to zero)
8 = 0 3x - 4 = 0 2x - 7 = 0
Since 8 is a constant, it does not lead to an answer.
for 3x - 4 = 0 add 4 to both sides
3x = 4 then divide both sides by 3
x = 4/3
for 2x - 7 = 0 add 7 to both sides
2x = 7 then divide both sides by 2
x = 7/2
2007-11-04 02:48:37 · answer #2 · answered by Scott K 2 · 0⤊ 0⤋
x= 4 and 7/2
2016-05-27 07:34:29 · answer #3 · answered by ? 3 · 0⤊ 0⤋
if you divide both sides by 8, you get (3x-4)(2x-7)=0, because anything divided by 0 is 0.
From here, you can go to ways. The first way, divide (2x-7) by both sides, so 3x-4=0, 3x=4, x=4/3.
Or, if you go the second way, divide (3x-4) by both sides, so you get 2x-7=0, 2x=7, x=7/2.
Therefore, [x= 4/3 or 7/2]
Hope this helps!
2007-11-04 02:47:34 · answer #4 · answered by none 2 · 0⤊ 0⤋
3x-4=0
x=4/3
or 2x-7=0
x=7/2
2007-11-04 02:41:59 · answer #5 · answered by someone else 7 · 0⤊ 0⤋