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the greatest possible acceleration and deceleration that a car can have r a and 2a rsptvly,and its max speed is v.Find the minimum time in which the car can cover a dist = s.

2007-11-04 01:25:59 · 1 answers · asked by anil p 1 in Science & Mathematics Physics

1 answers

Time needed for acceleration and deceleration is 3v/2a.
Distance needed for acceleration and deceleration is 3v²/4a.
Suppose that s is long enough to accelerate to maximum speed and to decelerate back to zero.
Then the minimum time is t=s/v + 3v/4a.
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2007-11-04 06:14:22 · answer #1 · answered by oregfiu 7 · 0 0

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