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Here goes:
Both Winifred and Winston collect model helicopters. Between them they have 200. If Winifred sold Winston 50, then Winston would have 4 times as many as Winifred. How many does Winifred have.

The working out must have an algebraic thingy in it it e.g winifred could be a, and winston b, etc.

2007-11-04 01:22:26 · 8 answers · asked by Anonymous in Science & Mathematics Mathematics

Thanks guys but im not that good at maths can you make it a bit clearer, i got the answer that starts YES ITS ALGEBRA

2007-11-04 06:50:38 · update #1

[continued from last edit]
but i dont know what he means when he says SUBSTITUTION or where he got 5a from ... thanks in advance.

2007-11-04 06:51:56 · update #2

8 answers

a = Winston, b = Winifred.

a+b=200
4a = b

Substitution.

5a = 200

a = 40. b = 160 (that's after he sold 50).

So, to start, Winifred has 90, Winston has 110.

2007-11-04 01:31:24 · answer #1 · answered by ? 7 · 0 0

It's a problem involving 2 equations.
If Winifred's model helicopters are represented X and Winston's by Y, then our first equation is

X + Y = 200

The problem states that if Winifred sold Winston 50, Winston would have 4 times as many model helicopters than Winifred. Thus,

X - 50 = 4y or Y= (X - 50) ÷ 4

Plugging our second equation into the first yields

X + (x-50) ÷ 4 = 200

Multiplying both sides by 4 gives us

4x + x - 50 = 800
5x - 50 = 800
5x = 850

X = 170 is the number of Winifred's model helicopters

We solve for Y using our value for X by substituting it in our second equation

Y = 170 - 50 ÷ 4
Y = 120 ÷ 4
Y = 30

120, our new value for X, is 4 times that of our value for Y.

2007-11-04 09:39:17 · answer #2 · answered by Quizzerian 1 · 0 0

Winifred = x
Winston = y
x+y = 200 (i)
(y+50) = 4(x-50)
y + 50 = 4x - 200
y = 4x - 250 (ii)

substitute (ii) into (i):

x + y = 200
x + 4x -250 = 200
5x - 250 = 200
5x = 450
x = 90

Therefore,
Winifred has 90 helicopters.
Winston has 110 helicopters.

You can see that this makes sense: If Winifred sells 50 helicopters to Winston, Winifred will have 40 helicopters and Winston will have 160 helicopters. 4*40 = 160

2007-11-04 09:39:04 · answer #3 · answered by James B 2 · 0 0

What is easiest is to choose a variable for One of them, say Winston has x helicopters, and then say that the other (Winifred) has 200 - x helicopters since together they have 200.

Now x + 50 would equal 4 [(200 - x) - 50] since Winston has 50 more than before and Winifred has 50 less.

x + 50 = 4(200 - x - 50)
x + 50 = 800 - 4x - 200

and you can solve for x


If you have to use two variables the equations would be, using your variables,
a + b = 200
(b + 50) = 4(a - 50)

b + 50 = 4a - 200, or 4a - b = 250

4a - b = 250
a + b = 200.....add together to get
5a = 450 and go from there

2007-11-04 09:27:50 · answer #4 · answered by hayharbr 7 · 0 0

Winifred=a
Winston=b

a-b=200
b+50=4(a-50)

Solve this two equations together.

2007-11-04 09:28:22 · answer #5 · answered by iyiogrenci 6 · 0 0

40

2007-11-04 09:43:59 · answer #6 · answered by Anonymous · 0 0

37 or 38 cause 200-50=150 then wiston would have 4 times more so winifred would have 37 0r 38

38 time 4 equal 152

37 times 4 equal 148

2007-11-04 09:32:12 · answer #7 · answered by Anonymous · 0 1

YES IT IS ALGEBRA

F(WINIFRED)
N(WINSTON

F+N=200
F-50=1/4(N+50)
MULTIPLY BY4
4F-200=N+50
N=4F-250
F+4F-250=200
5F=450
F=90
CHECK
90-50=40
40*4=160
40+160=200
Winifred has 90
Winston has 110

2007-11-04 09:40:43 · answer #8 · answered by GOLD-FLAW 2 · 0 0

it is easy what you do is get 200 -50=150+150+150+150 =600

2007-11-04 10:41:42 · answer #9 · answered by Anonymous · 0 0

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