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i have a quiz tomorrow and need some help

1. write the standard form of the equation of the line that is parallel
to the graph of y=2x -3 and passes through the point at (1,-1)

2. write the standard form of the equation of the line that is perpendicular to the graph of y=2x -3 and passes through the point at (6,-1)

2007-11-04 01:05:29 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

1)
y=2x -3
slope is 2
y-(-1)=2(x-1)
y=2x-2-1
=2x-3

2) m1*m2=-1
m1=2
m2=-1/2

y-(-1)=-1/2 (x-6)
y=-x/2+3-1
=-x/2+ 2

2007-11-04 01:15:18 · answer #1 · answered by iyiogrenci 6 · 0 0

via fact it must be perpendicular to the equation, this potential your slope = -a million/3 (perpendicular lines have slopes that are unfavourable reciprocals) Now your equation in y= mx + b variety is y= -a million/3x + b. Plug in the element (-6,4) to locate "b". y = -a million/3x + b 4 = -a million/3(-6) + b 4 = 2 + b 4 - 2 = b b = 2 consequently, your very final equation is y = -a million/3x + 2. desire i helped! :)

2016-11-10 05:50:04 · answer #2 · answered by Anonymous · 0 0

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