1, 4, 7 ,10 1,3
Work out the expression, in terms of n, for the nth term of the sequence.
i really dont know how to do this - can you please help me?? i havent got a clue and ive got an exam on it tommorrow!! help!!
2007-11-04 01:30:04 · 6 answers · asked by x_joanne_m_x 1 in Science & Mathematics ➔ Mathematics
Hi,
Your first term is 1 and every term after that is 3 larger than the previous term. that makes this an arithmetic sequence. Its general formula for the nth term is a(n) = a(1) + d(n - 1) where a(n) is the nth term, a(1) is the first term, d is the common difference that is added each time, and n is the number of the term you are trying to find.
For this set of numbers your equation is a(n) = 1 + 3(n - 1). This could be simplified into a(n) = 1 + 3n - 3 or a(n) = 3n - 2.
I hope that helps you!! I hope you do well on your test! :-)
2007-11-04 01:43:17 · answer #1 · answered by Pi R Squared 7 · 0⤊ 1⤋
1,4,7,10,13..
The sequence keeps adding 3, so you have an arithmetic sequence where the common difference, d = 3
The a1 term is 1 and you want to find the formula for any term, or the nth term.
Formula to start with is an = a1 + (n-1)d
an = 1 + (n - 1) (3)
an = 1 + 3n - 3
an = 3n -2
Note: the n on "an" is a subscript. So if you were wanting to find the 250th term of the sequence, a250 = ?
You put a 250 into the equation: 3(250)- 2 = 748
2007-11-04 01:41:27 · answer #2 · answered by Linda K 5 · 0⤊ 1⤋
For the 1st one i'm doing the solutions to coach you what to do: So 2n+2 1st term: 2(a million )+2. 4 2d term:2(2 )+2. 6 third term:2(3 )+2. 8 4th term:2(4 )+2. 10 5th term: 2(5 )+2. 12 10th term:2(10 )+2. 22 it works with all words via the way. Nth term works like counting a million via a million so if it asks you for the seventieth term replace n with 70. in case you're asked to do the 5 hundredth term replace n with 500. i'm hoping it facilitates. only no longer the bracket shows the two is timed via the style interior the bracket.
2016-10-14 23:48:59 · answer #3 · answered by stinnette 4 · 0⤊ 0⤋
It is 3n-2
eg Term 1 - 1*3=3 3-2=1
Term 2 - 2*3=6 6-2=4
etc
2007-11-04 01:09:46 · answer #4 · answered by Anonymous · 0⤊ 1⤋
The sequence must be
1, 4, 7 ,10, 13
4-1=3
7-4=3
10-7=3
13-10=3
So the common difference is d=3
a_1=1
General term is
a_n=a_1+(n-1)*d
The answer is
a_n=1+(n-1)*3
2007-11-04 01:40:08 · answer #5 · answered by iyiogrenci 6 · 0⤊ 1⤋
i will try to figure it out, but if I do, check if i am even right with some of the other answers, cause im only in 6th grade
2007-11-04 01:39:08 · answer #6 · answered by ♥<(^-^)>♥ 2 · 0⤊ 1⤋