Algebra 2: Factoring?

Question

Hey, i have done some factoring but i came across one that is not like the others. I've seen this a couple of times before and i ran through my notes a few times because i thought i copied it down but it appears i had not. If you can factor this one out for me, i can use it as a template for the rest. Thanks for your help.

r^2+4rs+4s^2

Answer 1

(r + 2s)(r + 2s) = (r + 2s)²

Answer 2

To answer this question just use the format:

(a +/- b)^2 = (a^2 +/- 2ab + b^2)

If you look at 4s^2 you'll see it's the same as (2s)^2,
and 4rs is the same as 2(r)(2s)

so you can set your "a" value to "r", and your "b" value to "2s":
r^2 + 4rs + 4s^2 = (r + 2s)^2

Answer 3

r^2 + 4rs + 4S^2 = (r + 2s)^2

Answer 4

(r+2s)(r+2s) or (r+2s)^2
Its trinomial squares.
I just learned this in Algebra 1
This relation is given in the book:
A^2 + 2AB + B^2 = ( A+ B)^2

Answer 5

r^2+4rs+4s^2=(r+2s)(r+2s)=(r+2s)^2

Answer 6

(r+2s)(r+2s)

=use the reverse of FOIL method...

Answer 7

(r+2s) (r+2s)

as simple as that...

Answer 8

(2s + r)^2

i think