Trig - How to find periods?

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Trig - How to find periods?

1. Find the period of y = -2 sin (8x + pi/2)

2. Find the period of y = 9/8 sin (- (8 pi x) / 3 )

Could someone please explain these questions? Thanks.

2007-11-03 18:17:40 · 2 answers · asked by labelapark 6 in Science & Mathematics ➔ Mathematics

2 answers

given... y = A sin (kx + b)

the period is 2pi/|k|

thus for the first one...
its pi/4

for the second one...
its 1/4.

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2007-11-03 20:22:13 · answer #1 · answered by Alam Ko Iyan 7 · 1⤊ 0⤋

8x + pi/2=2pi
8x=3pi/2

x=3pi/16

- (8 pi x) / 3
=(-6pi/3 -2pi)x/3
period is -2pi/3

2007-11-03 18:58:28 · answer #2 · answered by iyiogrenci 6 · 0⤊ 0⤋