find the first partial with respect to x of f(x,y,z) = z - sqrt(x^2-y^2), I don't see how the first partial is -x/2, i get -x/sqrt(x^2+y^2) what am I doing wrong?
2007-11-03 17:33:08 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
you are correct.
the answer is -x/sqrt(x^2+y^2).
Where does it say it's -x/2 ?
furthermore, the degree of the function must be 1 less since the derivative is taken.
The degree of your original function with respect to x is "1", since 2*(1/2) = 1.
Thus the degree of the derivative must be zero.
the degree of x/2 is 1, not zero.
However, the degree of -x/sqrt(x^2-y^2) = 1/(2*(1/2)) = 1/1 = 1.
2007-11-03 17:51:25 · answer #1 · answered by Anonymous · 0⤊ 0⤋
With respect to which variable is the derivative required? x or y or z?
2007-11-04 00:43:57 · answer #2 · answered by Madhukar 7 · 0⤊ 0⤋
Nothing as far as I can see.
2007-11-04 00:43:25 · answer #3 · answered by cattbarf 7 · 0⤊ 0⤋
pff lol
2007-11-04 00:36:15 · answer #4 · answered by KiRby 2 · 0⤊ 1⤋