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Given any rational number a and for any positive rational number ε , we can always find another rational number b such that │a-b│< ε .

2007-11-03 17:04:37 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

Remember that the absolute value is the undirected distance between two values on the number line. The conjecture you've offered is that for each pair of rational a and ε with ε > 0, there exists rational b within ε of a.

│a - b│< ε implies ±(a - b) < ε

For a – b < 0,

│a - b│ = -(a – b)
│a - b│ = b – a

Thus,

b – a < ε

implies

b < ε + a

b is rational by the closure property.

For a – b ≥ 0,

│a - b│ = a – b

Thus,

a – b < ε

implies

a – ε < b

again, b is rational by the closure property.

2007-11-03 18:01:34 · answer #1 · answered by richarduie 6 · 0 0

Of course you can

Let b = a+ε/2

2007-11-03 17:12:15 · answer #2 · answered by Ranto 7 · 0 0

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