108 doesn't have a nice, integral square root, but the teacher doesn't want you to reach for a calculator. You're supposed to apply this property of square roots:
√(a∙b) = (√a)(√b)
and you need to factor 108 into primes first: 108=2∙2∙3∙3∙3
So, √(108) = √(2∙2) ∙ √(3∙3) ∙ √3
= 2∙3∙√3
= 6√3
2007-11-03 11:59:16
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answer #1
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answered by DWRead 7
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First, you should determine what numbers are factors at 108 (numbers that multiply to equal 108.) Well, you should find that 36 * 3 = 108. So, now, your sqrt(108) can be written as sqrt(36*8). We know what the square root of 36 is don't we? In fact, it is 6. So, we remove the 36 from the square root to get 6*sqrt(3).
I hope this was clear enough. I'm not sure what grade you are in.
2007-11-03 11:44:28
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answer #2
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answered by Matthew 1
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Split 108 into it's prime numbers:
108/2 = 54
54/2 = 27
27/3 = 9
9/3 = 3
3/3 = 1
Therefore 108 = 2*2*3*3*3
Square root means same # multiplied by same #.
Out of 2*2*3*3*3, there is two 2s and three 3s. That means you can take out two 2s and two 3s.
sqrt (108) = sqrt (2*2*3*3*3) = 2 * sqrt(3*3*3) = (2*3) * sqrt (3)
answer = 6 * sqrt (3)
2007-11-03 11:41:23
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answer #3
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answered by megamxtreme 1
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4 square root of 6
2007-11-03 11:37:23
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answer #4
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answered by Ms. Exxclusive 5
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root (108) is equivalent to
root (27 * 4) writing this another way
root (27) * root (4) or
2 * root (27), now
root (27) is equivalent to
root (9) * root (3), which is
3 * root (3)
so 2 * 3 * root (3) is
6 root (3)
2007-11-03 11:40:19
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answer #5
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answered by plateausproblem 3
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sqrt of 108
sqrt of 36 * sqrt of 3
6 sqrt of 3
2007-11-03 12:20:31
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answer #6
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answered by Dave aka Spider Monkey 7
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get a calculater. The answer is 10.39230485
Hope this helps:p
2007-11-03 11:38:59
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answer #7
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answered by Chaz 2
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_______
v (36)(3)
____
6 v3
2007-11-03 11:44:21
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answer #8
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answered by Doc Holiday 2
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