Solve: x^2 is >= 2x + 24?

Question

has to be written in this form......(x l -4 <= x <= 6)

Excuse me little miss 16 year old brat know it all Meg - whatever. I had my answer in the question and wanted to make sure it was right. Sorry for wanting get good grades and do more with my life than be a tattoo artist and body piercer.

Answer 1

x^2 >= 2x + 24

Move everything to the left hand side.

x^2 - 2x - 24 >= 0

Complete the square.

x^2 - 2x + 1 - 24 - 1 >= 0
(x - 1)^2 - 25 >= 0
(x - 1)^2 >= 25

|x - 1| >= 5, which means

-5 <= x - 1 <= 5, or

-4 <= x <= 6

Answer 2

while working with absolute values, remember that the quantity interior the | | has 2 values, one beneficial and one damaging, so there will be 2 conceivable suggestions. Set the quantity to each and each value and remedy for the unknown. | x² + 2x - 36 | = 12 ± (x² + 2x - 36) = 12 If x² + 2x - 36 = 12, x² + 2x - 36 - 12 = 0 x² + 2x - 40 8 = 0 (x + 8)(x - 6) = 0 If the made from 2 words equals 0, then one or the two words equivalent 0. If x + 8 = 0, x = - 8 If x - 6 = 0, x = 6 If - (x² + 2x - 36) = 12, - x² - 2x + 36 = 12 - x² - 2x + 36 - 12 = 0 - x² - 2x + 24 = 0 - (x - 4)(x + 6) = 0 If - (x - 4) = 0, - x + 4 = 0 - x = - 4 x = 4 If x + 6 = 0, x = - 6 x { - 8, 4, ± 6 } ¯¯¯¯¯¯¯¯¯¯¯¯

Answer 3

x l -4 <= x <= 6

Answer 4

x^2>=2x+24
x^2-2x-24>= 0
(x-6)(x+4)>=0
x<=-4 x<=6

Answer 5

hahaha, can you not do your own homework?

hahahaha, also neurosurgeon...but you know, i dont expect you to know what that is.
and what does my age have to do with this since I did that in math about two weeks ago.