For physic people, help.?

Question

A 1500.0 N force is exerted on a 200.0 kg crate to move it across the floor. If the coefficient of friction is 0.250, what is the crate's acceleration?

I need some guidence in this one. Thanks...please!

Answer 1

Force equation
F=Fa-f

Fa - force applied
F - resulting force
f - force of friction

Then since Fa-f=ma
a= (Fa - umg)/m
a= (1500.0 - 0.250 x 200.0 x 9.81)/200.0=
a=5.05 m/s^2