solve the right triangle. round results to an appropiate # of significant digits.?

Question

B= 39.3 degrees, C= 4.3 mm

Answer 1

4.3/ sin90 = b/ sin39.3 --> b = 4.3sin39.3 = 2.7mm
a = sqrt(c^2-b^2 = sqrt(4.3^2-2.7^2) = 3.3 mm
3.3/sinA = 4.3 --> A = arcsin 3.3/4.3 = 50.1 degrees
So B = 90-50.1 = 39.9 degrees

Answer 2

since triangle is right angled

one angle = 90 degrres

B = 39.3 degrees

other angle = 90 - 39.3 = 50.7 degrees

apply sin rule

a/sin A = b/sinB = c/sinC

a/sin 90 = b/sin 39.3 = 4.3/sin 50.7

a/1 = b/0.633 = 4.3/0.774

a = 4.3/0.774 = 5.55 mm

b = 0.633 (4.3/0.774) = 5.55*0.633 = 3.512 mm

Answer 3

you ask a lot of questions on here. I doubt this will benefit you when you are taking the exam.
c=hyp
y/hyp = sine (angle)
x/hyp=cosine (angle)

you can figure out which side is x and which is y on your own.

Answer 4

Umm you are kind of a loser to get other people to do ur homework...