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So in my school the semester grade is as follows.

40% cardmarking 1
40% carmarking 2
20% Final Exam So i need to know the formula to see what grade I have to get on my final to get a certain grade in the class

2007-11-03 09:43:43 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

Suppose
A = your grade in cardmarking 1
B = your grade in cardmarking 2
E = your score on the final exam
G= your final grade

Then,

.40A + .40B +.20E =G

So if you know A and B, and you know the value of G you are shooting for, solve this equation for E. The score you need on the final exam is

E = (G - .40A -.40B) / .20

this simplifies to

E = 5G - 2A - 2B

2007-11-03 09:54:44 · answer #1 · answered by Michael M 7 · 0 0

You should be patient and wait for responses to your questions instead of reposting questions, but here is the answer I gave for your previous question just posted again:

If I understand the question correctly:
Let's say you got an 80% in the first marking period, you then multiply that number by .40 (because the first marking period is worth .40 of the total points available) and you get 32. Then lets say you get a 75% in the second marking period you then do the same, 75 * .40 and you get 30. You then add the two values you have already gotten (30+32) and you get 62. The highest amount you could get on the final is 20% so if you theoretically got a 100% on the final the most you could then add to the 62 is (100 * .20 = 20) 20 points and the highest grade you could have in the class is an 82.

Or in general the formula would be (A * .4) + (B * .4) + (C * .2)
Where A is the first marking period grade, B is the second marking period grade and C is the final grade.

If you want to figure out what you should *aim for* as a lowest grade in order to get the lowest grade on the final and still get an A in the class the formula would be as follows:
(90 - [(A * .4) + (B * .4)]) / .2 = C

2007-11-03 09:48:52 · answer #2 · answered by adidas55dude 2 · 0 0

X = the final grade in the class
y = the grade you need to make on the final
f = the grade you have on the cardmarking 1
s = the grade you have on the cardmarking 2
I assume you know X, f and s
.4f + .4s + .2y = X
Multiply each by 5
2f + 2s + y = 5X
y = 5X - 2f - 2s

Say you want to end up with 80 as the semester grade and you had 72 on card 1 and 78 on card 2.
y = 5*80 - 2*71 - 2*74 = 110 (probably out of reach)
If you're in this situation, talk to the teacher about doing a project for extra credit

But if you want to end with 80 and had 78 and 79 on the two cards, then:
y = 5*80 - 2*78 - 2*79 = 86 (probably doable with more study)

2007-11-03 09:55:24 · answer #3 · answered by Steve A 7 · 0 0

.40(cardmarking 1 grade)+.40 (cardmaking 2 grade) +.20 (final grade needed) = desired grade

[0.4(card marking grade) + 0.4 (card marking grade 2) - (desired grade)]/-0.20 = final grade needed

2007-11-03 09:51:53 · answer #4 · answered by Anonymous · 0 0

(0.4) x score from cardmarking 1 + (0.4) x score from carmarking 2 + (0.2) x score from final exam = total percentage

2007-11-03 09:49:58 · answer #5 · answered by bustedtaillights 4 · 0 0

x= grade cardmarking 1
y = grade card marking 2
F = grade on final
G= desired grade
.4(x+y) +.2F =G
F = 5[G-.4(x+y)]

2007-11-03 09:56:12 · answer #6 · answered by ironduke8159 7 · 0 0

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