more tough physics help?

Question

1. A baseball is thrown at an angles of 22degrees relative to the ground at a speed of 27.1m/s. The ball is caught 52.0 m from the thrower.
a) How long is it in the air?(I had the correct answer on this one which was 2.0695131 seconds)
b) How high is the tallest spot in the balls path?(I used the whole time it was up and then divided it in half to get 5.42820082m which was wrong)

2. A quarterback throws the football to a stationary receiver who is 26.7m down the field. The football is thrown at an initial angle of 36.5degrees to the ground.
a) At what initial speed must the quarterback throw the ball for it to reach the receiver?
b) What is the ball's highest point during its flight?
I had both wrong, but i dont see how i missed a when i used the same equations as above, but my answers were 18.2274788 and 13.2032173 respectively.

Answer 1

1. Vertical and horizontal components are
Vv= Vsin(22)
Vh=Vcos(45)

a)t2=S/Vh

b)h=0.5 gt1^2 where
t1=Vv/g then
h=0.5 g (Vsin(22)/g)^2
h=0.5 Vsin(22)^2 /g

2. Lets assume that receiver and quarterback are about the same height :-)

t(total) =t (up) + t (down)=2t
t=V sin(36.5) / g
Vh=S/2t= S/ 2 [V sin(36.5) / g]
Vh= Vcos(36.5) = Sg/ [2V sin(36.5)]

V^2 = S g /[2 cos(36.5)sin(36.5)]
V=sqrt(S g / sin( 73))

b) h= 0.5gt^2