No!
The density of ice is less then water. That means that when ice will met there will be room to spare.
(Linear expansion was not considered since the final temperature was not specified. )
2007-11-03 08:07:14
·
answer #1
·
answered by Edward 7
·
0⤊
1⤋
The answer is "No." When you placed ice inside of that glass and filled it up with water, the "ice" itself is already a part of the total volume of the glass. For instance, if you filled up a whole cup of glass with water and put it in the freezer until it has reached the freezing point, then you take it out....the water inside of the glass will become ice...here is the question...when you want to melt this full glass of ice, will it over flow or will not over flow.....it's the same logic as your question....the answer is "no"
2007-11-03 08:12:32
·
answer #2
·
answered by jaccchen23 2
·
0⤊
0⤋
No, neither will there be "room to spare" as Edward claims. The water level after melting will be the same place at the top of the glass (thermal expansion of glass and buoyancy in air neglected). Why? Although a given mass of ice before it melts takes up a greater volume due to its lower density, since it floats (sticking *above* the rim), it displaces an amount of liquid water equal to its own weight. Therefore, when it melts (and has the same density as the originally displaced liquid), it will take up the same volume as the originally displaced liquid.
2007-11-03 08:40:58
·
answer #3
·
answered by Dr. R 7
·
0⤊
1⤋
no because the volume of the ice cubes is counting towards the water level @ the top of the glass, the water melted from the ice cubes volume is equal to the ice cubes volume when it was unmelted (sry thats a little confuseing)
2007-11-03 08:07:30
·
answer #4
·
answered by hockeyman25158 2
·
0⤊
0⤋
No
2007-11-03 08:09:42
·
answer #5
·
answered by A W 5
·
0⤊
0⤋