6n^2-23n+7
thanks
2007-11-03 07:48:06 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
6x² - 23n + 7 = 0`
The middle term is - 23n
Find the sum of the middle term
Multiply the first term 6 times the last term 7 equals 42 and factor
Factors of 42
1 x 42
2 x 21. . .←. .use these factors
3 x 14
6 x 7
- 2 and - 21 satisfy the sum of the middle term
insert - 2n and - 21n into the equation
6n² - 23n + 7 = 0
6n² - 2n - 21n + 7 = 0
Group factor
(6n² - 2n) - (21n + 7) = 0
2n(3n - 1) - 7(3n - 1) = 0
(2n - 7)(3n - 1) = 0
- - - - - - - - s-
2007-11-03 08:05:51 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
To think about this best, we need to have it as an equation.
6n^2 - 23n + 7 =0
This factorizes to:
(3n - 1)(2n -7) = 0
If you cannot see these roots straight away, you can solve it using the quadratic formula and then play with different values until the factorization is correct.
2007-11-03 08:23:05 · answer #2 · answered by tinned_tuna 3 · 0⤊ 0⤋
6n² - 23n + 7
(3n - 1)(2n - 7)
2007-11-03 08:32:46 · answer #3 · answered by Como 7 · 0⤊ 1⤋
6x7=42=21x2=-21x-2
and -21-2 = -23
6n^2-21n-2n+7=2n(3n-1)-7(3n-1)
=(2n-7)(3n-1)
2007-11-03 07:56:34 · answer #4 · answered by mr.integral 3 · 0⤊ 1⤋
(3n-1)(2n-7)
2007-11-03 07:54:28 · answer #5 · answered by Ms. Exxclusive 5 · 1⤊ 1⤋