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What is the maximum load that could be suspended from a copper wire of length 1.5 m and radius 1 mm without breaking the wire? Copper has an elastic limit of 2 × 10^8 Pa and a tensile strength of 4.1 × 10^8 Pa.

2007-11-03 05:52:20 · 2 answers · asked by Anonymous in Science & Mathematics Physics

2 answers

Assuming no change in radius as the wire is stretched, the tensile stress T = F/A (area) so F = AT.
A = pi*0.001^2
F = pi*0.001^2*4.1E8 = 1288 N

2007-11-03 09:19:28 · answer #1 · answered by kirchwey 7 · 0 0

If the entire time from bounce to max suited then each and every of how all the way down to floor back is two.8 s, the time to be triumphant in max suited is a million/2 of two.8 s via using symmetry of time, distance, and speed of "unfastened-fall" action. d = a million/2gt² {the placement d = max suited, g = 9.80 one, t = a million.4} d = (0.5)(9.80 one)(a million.4)² = 9.6 m ANS fact: formula used is for the section = d, as ball *falls* from relax to floor in a million.4 s, and not the formula for the ball as a results of fact it *rises* from bounce to max suited. The formula are diverse in each and every and each case, in spite of the undeniable fact that the respond is an identical via using certainty of action symmetry.

2016-11-10 03:48:09 · answer #2 · answered by ? 4 · 0 0

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