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At the surface of a freshwater lake the air pressure is 1.1 atm. At what depth under water in the lake is the water pressure 4.5 atm?
m

2007-11-03 03:34:02 · 2 answers · asked by sportzblock 1 in Science & Mathematics Physics

2 answers

First of all, the guy above my answer is a jerk off. Now onto the real answer.

Use the equation P=Patm + pgd
P=pressure at unknown depth=4.5 atm
Patm=pressure of atmosphere=1.1 atm
little p=density of H2O=1000 kg/m^3
g=9.8 m/s^2
d=depth (unknown)

To make your life miserable, they give the pressures in atm, meaning you will have to convert to Pascals.
4.5atm*101.3 kPa/atm*1000 Pa/kPa=455850 Pa (P)
1.1 atm*101.3 kPa/atm*1000 Pa/kPa=111430 Pa (Patm)

P=Patm + pgd
455850-111430=1000*9.8*d
d=35.14 m

2007-11-04 11:05:09 · answer #1 · answered by carrerasarah 2 · 1 0

Don't worry about the depth, you've got more important things to worry about. I'd head to port ASAP, because of the record high pressure system that just blew in.

2007-11-03 04:51:41 · answer #2 · answered by Dr. R 7 · 0 1

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