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integral of (x^3 + x) / x ?

i get x^3/3 + x + c

2007-11-02 19:18:25 · 5 answers · asked by alex m 1 in Science & Mathematics Mathematics

they get x^2/2 + logx +c

2007-11-02 19:22:47 · update #1

5 answers

I = ∫ x ² + 1 dx
I = x ³ / 3 + x + C

2007-11-03 00:56:07 · answer #1 · answered by Como 7 · 0 1

(x³+x)/x = x²+1
=x³/3 + x + c

2007-11-02 19:25:49 · answer #2 · answered by Anonymous · 1 0

Your answer is correct for the stated problem.
x^2/2 + logx + c = ∫(x^3 + x)dx / x^2

2007-11-02 19:37:40 · answer #3 · answered by Helmut 7 · 0 1

I agree, you are correct.

Where in the hell did the log come from?

2007-11-02 20:15:28 · answer #4 · answered by Randy C 2 · 0 0

you are correct

2007-11-02 19:21:59 · answer #5 · answered by ? 5 · 1 1

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