I was in a restaurant/ bar in LA, without my knowledge, I was charged a mandatory $90 for a tip on 1 bottle of liquor. Is this legal? Please help. Thank you.
2007-11-02 12:55:47 · 7 answers · asked by Mystic 1 in Business & Finance ➔ Careers & Employment ➔ Law & Legal
Not sure, but it would seem if they tell you in advance, it's really a service charge, not a tip, and it's ok. E.g., menu says, "Parties of 6, 15% gratuity added to check." If it was a total surprise, and it's not posted anywhere on the wall, the menu, whatever, then it sounds iffy.
2007-11-02 12:59:58 · answer #1 · answered by heart_and_troll 5 · 1⤊ 0⤋
Are you sure the $90 was the tip or for the bottle and tip or were you confused after drinking the bottle? I know it is legal for restaurants to charge a 20% gratuity on parties of 8 or more people so the waitstaff doesn't get stiffed after working their tail off to serve everyone.
2007-11-02 13:41:12 · answer #2 · answered by Ryan's mom 7 · 0⤊ 0⤋
You should question the charge with the manager first, and he can explain it to you. If you aren't happy to pay for that, and I think you can work something out with the manager.
If it wasn't written anywhere, then it is illegal.
If it is on the menu, and you didn't read it, then he has to show it to you.
But always ask the charges at the moment. When you sign your check, it means you are AGREED to pay for it.
2007-11-02 13:19:59 · answer #3 · answered by paobay 4 · 0⤊ 0⤋
It sounds as if it was a "corkacge" fee on a bottle of wine. It is legal, but it should have been disclosed t o you, first.
2007-11-02 13:14:09 · answer #4 · answered by everyone's mom 4 · 0⤊ 0⤋
No, because a tip is gratuity which is something given voluntarily or beyond obligation for services.
2007-11-02 13:09:29 · answer #5 · answered by Anonymous · 0⤊ 0⤋
You can mark through it and not pay. You only have to pay for what you received.
2007-11-02 14:17:46 · answer #6 · answered by Squat1 5 · 0⤊ 0⤋
if it is disclosed to you first yes
2007-11-03 19:59:53 · answer #7 · answered by Dan 2 · 0⤊ 0⤋